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One thing you might notice in the preceding code samples is that it wouldn t take long before our Counter variable exceeds the number of programs in our sequence or goes to a negative number. It would be wise for us to add some code to either prevent the Counter value from going below 0 or go higher than the number of programs we will actually need to run in our sequencer. We can add a new My Block to our code that will handle the math for us and not allow the value to go out of range. In our example, the sequence range is 0 through 4. We are currently using Math blocks to increment or decrement our Counter value, so all we need to do is create a new My Block called SequenceMath block. The code would look like Figure 11 7. The logic for this new program will be as follows: 1. 2. 3. 4. 5. 6. 7. 8. 9. Input current sequence value. Input true or false if we are incrementing or decrementing the sequence value. Assign, the current sequence value to the Sequence variable. If we are incrementing, follow the true branch; otherwise, follow the false branch. In the true branch, add 1 to the Sequence variable. Check if the Sequence variable value is greater than the UpperLimit constant (which has a value of 4 in our example). If the Sequence value is greater than the UpperLimit constant, assign the LowerLimit constant to the value of the Sequence variable. In the false branch, subtract 1 from the Sequence variable. Check if the Sequence variable is less than the LowerLimit constant (which has a value of 0 in our example).

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This operator is similar to Select because it allows us to define the elements to pick from a sequence. The difference is in the return type.

In descending order of preference, those are Stonyfield cream-top, Fage cultured cream, and Lifeway Greek-style kefir Alrighty then, let s create an object named fridge with boolean members indicating what my cultured milk options are Life is good tonight because I do have Brown Cow in there: var fridge = { brownCow: true, stonyfield: false, fage: true, lifeway: false }; var smoothie; Now we want JavaScript to choose my favorite available yogurt or kefir by testing the following four expressions in order from top to bottom: fridgebrownCow fridgestonyfield fridgefage fridgelifeway But an if condition can test only one expression So, do we write four of those in a row It s sort of a clunky solution, but let s do it in Firebug.

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30 Jun 2016 ... The following code illustrates an example where we generate a DataMatrix and return it as a Base64 encoded String, including returning an ...

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<Extension> _ Public Shared Function SelectMany(Of T, S)(ByVal source As IEnumerable(Of T), _ ByVal selector As Func(Of T, IEnumerable(Of S))) As IEnumerable(Of S) <Extension> _ Public Shared Function SelectMany(Of T, S)(ByVal source As IEnumerable(Of T), _ ByVal selector _ As Func(Of T, Integer, IEnumerable(Of S))) _ As IEnumerable(Of S) With the IEnumerable(Of S) type returned by the selector parameter of SelectMany, it s

Note that, for this to work, we have to test the four expressions from bottom to top so that the best available yogurt goes into my smoothie: var fridge = { brownCow: true, stonyfield: false, fage: true, lifeway: false }; var smoothie; if (fridgelifeway) { smoothie = "Lifeway Greek-style kefir"; } if (fridgefage) {.

10. If the Sequence value is less than the LowerLimit constant, assign the UpperLimit constant to the value of the Sequence variable. 11. Output the Sequence variable value.

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smoothie = "Fage cultured cream"; } if (fridge.stonyfield) { smoothie = "Stonyfield cream-top yogurt"; } if (fridge.brownCow) { smoothie = "Brown Cow cream-top yogurt"; } smoothie += ", grass-fed cream and milk, Saigon cinnamon, and wild blueberries." // "Brown Cow cream-top yogurt, grass-fed cream and milk, Saigon cinnamon, // and wild blueberries." Although this kludge works, it makes us look like bumpkins to JavaScript-savvy programmers because we test for every variation, even if we ve previously found a match. There is a better way, right Yup, you betcha. First, reorder the if conditions in descending order of preference. Second, nest if conditions two through four in an else clause for if conditions one through three. We ve now got some opt-outs if an if condition is true; in other words, we don t go on and test for every variation after an if condition is found to be true. var fridge = { brownCow: true, stonyfield: false, fage: true, lifeway: false }; var smoothie; if (fridge.brownCow) { smoothie = "Brown Cow cream-top yogurt"; } else { if (fridge.stonyfield) { smoothie = "Stonyfield cream-top yogurt"; } else { if (fridge.fage) { smoothie = "Fage cultured cream"; } else { if (fridge.lifeway) { smoothie = "Lifeway Greek-style kefir"; } } } } smoothie += ", grass-fed cream and milk, Saigon cinnamon, and wild blueberries." // "Brown Cow cream-top yogurt, grass-fed cream and milk, Saigon cinnamon, // and wild blueberries." This is more elegant, but we can do even better by using the else if idiom. So, click Clear in both Firebug panels, and enter and run the following: var fridge = { brownCow: true, stonyfield: false, fage: true, lifeway: false }; var smoothie;

possible to concatenate many projection operations together, either on different sequences or starting from the result of a previous query. The SelectMany operator extends the IEnumerable(Of T) type. The selector parameter has two formats: the first returns the IEnumerable(Of S) type and the second also requires a zero-

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