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Solution to Exercise 15-1. Create the following six strings: String 1: Hello String 2: World String 3 (a verbatim string): Come visit us at http://www.LibertyAssociates.com String 4: a concatenation of strings 1 and 2 String 5: world String 6: a copy of string 3 Once you have the strings created, do the following: 1. Output the length of each string. 2. Output the third character in each string. 3. Output whether the character H appears in each string. 4. Output which strings are the same as string 2. 5. Output which strings are the same as string 2, ignoring case. Creating the strings is relatively easy: you need to remember to keep the space in String 1 and to use a verbatim string (with an @ symbol) for String 3. You can concatenate Strings 1 and 2 using Concat( ) or the + operator, and you can use Copy( ) to create String 6. For the other parts of the exercise, you can just put all the code directly in Test( ). You could put all the strings into an array, and iterate over the array for each test, but with only six elements it s fine to test them each individually. For part 1, you just need to output the Length of each string:

Sec 8-4 8-4

Console.WriteLine( "s1: {0} [{1}]", s1.Length, s1 );

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The data in the schema contains the information to be used to control a database The information can be used to generate a database system and its processing functions, or its use can be deferred to the execution time of the processes that manipulate the database This choice is related to the concept of a binding time introduced in Sec 1-4 The schema, as written by the organizer of the database, has to be translated for use by a database-management system The binding choices are the familiar alternative of compiling versus interpretation In the environment of the database, compiling is equivalent to using all the information in the schema when the application programs are created; the schema can then be discarded Interpreting, on the other hand, is equivalent to the use of a general program that, when called upon to carry out database manipulations, looks at the schema to nd data items and determine their relationships 8-4-1 Examples of Schema Translation In order to clarify the alternatives, will sketch some examples of schema translation and schema use In Sec 8-4-2 we will summarize the relative advatages and disadvantages

Part 2 is also simple. To get the third character in each string, use the index operator, but remember that indexes start at zero, so the third character is at index [2]:

1 In practice, a directory or other data structure is used to keep track of free space, and records are inserted into the rst available free slot, as discussed in 7 This increases the cost of insertion and deletion a little, but not enough to a ect our comparison of heap les, sorted les, and hashed les

Console.WriteLine( "s1: {0} [{1}]", s1[2], s1 );

The schema in the RETRIEVE example (Fig 8-5) used in Sec 8-2-1 is simply stored in the form of an array on the schema le The translation process consisted only of formatting the three elds of each schema entry The schema subsequently was used interpretively Figure 8-11 shows a similar process for a more complete schema language Here, however, the source schema is analyzed and its elements are used to build tables and dictionaries for the interpreter shown in Fig 8-14 The dictionaries are used for recognizing the terms which appear in the user s commands, and the tables direct a set of interpreting routines to the contents of the database

For part 3, to determine whether there s a specific character in the string, you can use IndexOf( ) to test for that character. If the character isn t in the string, IndexOf( ) returns 1. Therefore, if the returned index is greater than or equal to zero, the character is in the string. To be completely accurate about it, you can use ToUpper( ) or ToLower( ) on each string first so that you re testing for both uppercase and lowercase instances of the character. We re using the ternary operator here (from 4) to return yes or nope :

Space Update Record size Equal Greater A D B C B D A F D C F D Retrieval Single Subset Exhausrecord tive E F B A A C D D D B F A B A B D E B

Console.WriteLine( "s1: {0} [{1}]", s1.ToUpper( ).IndexOf( 'H' ) >= 0 "yes" : "nope", s1 );

A = excellent, well suited to this purpose B = good C = adequate D = requires some extra e ort E = possible with extreme e ort F = not reasonable for this purpose

In part 4, you need to test whether a string is the same as String 2. That s what the String.Compare( ) method is for. Again, we re using the ternary operator for the output:

Only the multi-indexed le and the multiring les provide the capability for access to data according to more than one dimension These two methods provide the basic building blocks for le designs providing multiattribute access whenever there are many records Table 4-1 above lists these conclusions in a summary form

8

Console.WriteLine( "s1: {0} [{1}]", String.Compare( s1, s2 ) == 0 "Same!" : "Different", s1 );

Sec 4-1

Part 5 is very similar to part 4, but this time, you use the overloaded version of Compare( ) and set the third parameter to true so that Compare( ) will ignore case:

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